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| New Elementary Math 1 |
(1999
printing)
This page last updated
May 25, 2005
| Contents: 1.6 should say Least Common Multiple. | ||||
| Exercise 1.4 |
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| 4.(b) |
113 |
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| Lesson 1.5 |
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| p. 14 |
In Method 2 for extracting the common prime factors of 60 and 96, the number below the 96 should read 48 rather than 34. |
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| Exercise 1.8 |
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| 5.(h) |
A simpler solution is 48 x 24-n or 3 x 28-n . This problem, however, is not appropriate yet. |
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| Exercise 2.2 |
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| 6.(c) | Solution involves negative numbers or using the distributive property for -1 and rearranging. | |||
| 6.(e) | Solution involves negative numbers or rearranging. | |||
| Exercise 2.3 | ||||
| 6.(f) |
Solution involves negative numbers, which haven't been presented yet. |
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| Exercise 2.6 |
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| 8.(d) |
Solution involves negative numbers, which haven't been presented yet. |
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| Exercise 4.3 |
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| 9.(d) |
8,231,953 |
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| Exercise 6.5 |
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| 18. | The amount the man spent is $210, not $110 (in 1997 reprint, not later reprints) | |||
| Challenger 6 | ||||
| 5. |
"If she had spent the same amount of moenty for each type, whe would have bought 2 more cans of drinks for the same total amount of money." |
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| 7.1 Rate and Speed |
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| p.172 |
Rate Example (b) should have a 3 in the denominator of the fraction. |
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| Revision 2C |
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| 2.(b) |
True for x = 3 |
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| Miscellaneous Exercise 2 |
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| 14. |
Insufficent information. |
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| Miscellaneous Exercise 3 |
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| 12.(a) |
Insufficient information. |
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| Exercise 12.3 |
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| 19. | 2 : 3 | |||
| Exercise 14.1 | ||||
| 6.(b) | Change the top angle on the figure on the left to 120o. Answer for angle a is 120o. | |||
| 6.(c) |
Change the angle on the figure on the right to 23o. Answer for angle a is 23o. |
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| Revision 4C |
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| 1.(a) |
Answer is 31.5 cm2 |
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| 9. |
This problem inappropriate for this level since the solution involves use of the Pythagorean theorem. |
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| Miscellaneous Exercise 4 | ||||
| 13.(a) |
(ii) Inappropriate. Solution involves Pythagorean Theorem which hasn't been taught yet. | |||
| Assessment 1, Paper II |
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| 2.(b) |
The solutions in the text are for a sum of 23 along the side, not 21. |
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| Assessment 2, Paper I |
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| 2(b) |
The answer in the text are for 2 pumps working. The answer for 2 pumps not working is 20 h. |
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